多文件上传的例子 //upload_html.php--------------------------------------------------------------------------------------------- <HTML> <HEAD> <TITLE>上传文件</TITLE> </HEAD> <script> function beforesubmit(forma) { var indexnamea=forma.indexname.value; var upfilea=forma.upfile.value; var k=/ /g; var indexnamea=indexnamea.replace(k,""); var upfilea=upfilea.replace(k,""); if(indexnamea=="" upfilea=="") { alert("目录名称或上传的目录不能为空!"); return false; } return true; } </script> <BODY BGCOLOR=WHITE> <BR> <form name=form1 action="upload.php" method=post enctype="multipart/form-data" >n"; <table cellspacing="1" cellpadding="5" border="0" width="580" bgcolor="#C2E2F5"> <tr bgcolor="#E3F2FB" align="center"> <td width="280" align="center" height="30">上传的文件</td> </tr> <? for($i=1;$i<8;$i++) { $upfile="upfile".strval($i); echo " <tr>n"; echo " <td bgcolor=#F5FBFE width=264><input type=file name=$upfile lengh=25></td>n"; echo " </tr>n"; } ?> <tr bgcolor="#E3F2FB"> <td colspan="2" height="1"> </td> <td colspan="2" height="1"> <div align="center"> <input type=submit name="submit" value=上传> </div> </td> </table> </form> </body></html> //----------------------------------------------------------------------------------------------------------------------- //upload.php------------------------------------------------------------------------------------------------------------- //upload_path:文件要上传到的目录路径 <?php for($i=1;$i<8;$i++) { $upfile="upfile".strval($i); if(chop($$indexname)!="" and chop($$upfile)!="") { $upfilename=($upfile."_name"); $filename=upload_path.$$upfilename; $copyfile = copy($$upfile,$filename); if (!$copyfile) die("文件上传失败!"); $ls_file.=$$upfilename."n"; $flag=1 ; } } if($flag){ $ls_msg="文件n".$ls_file."上传成功!"; } else{ $ls_msg="无文件上传,请重新选择!"; } echo "<HTML>n" ; echo "<HEAD>n" ; echo "</HEAD>n" ; echo "<BODY >n" ; echo $ls_msg."n"; echo "</BODY>n" ; echo "</HTML>n" ; ?> By phpfans.net收集整理 |